(a.), (b.), (c.):
Rounding to two decimal places:
$
(a.)\;\;h(100) \approx 88.93\;feet \\[3ex]
(b.)\;\;h(200) \approx 155.71\;feet \\[3ex]
(c.)\;\;h(350) \approx 214.36\;feet \\[3ex]
$
(a.) The height of the golf ball after it has traveled a horizontal distance of 100 feet is
approximately 88.93 feet.
(b.) The height of the golf ball after it has traveled a horizontal distance of 200 feet is
approximately 155.71 feet.
(c.) The height of the golf ball after it has traveled a horizontal distance of 350 feet is
approximately 214.36 feet.
$
(d.) \\[3ex]
h(x) = 0 \\[3ex]
h(x) = \dfrac{-32x^2}{170^2} + x \\[5ex]
\implies \\[3ex]
0 = \dfrac{-32x^2}{28900} + x \\[5ex]
\dfrac{-32x^2}{28900} + x = 0 \\[5ex]
\dfrac{-32x^2}{28900} + \dfrac{28900x}{28900} = 0 \\[5ex]
\dfrac{-32x^2 + 28900x}{28900} = 0 \\[5ex]
28900\left(\dfrac{-32x^2 + 28900x}{28900}\right) = 28900(0) \\[5ex]
-32x^2 + 28900x = 0 \\[3ex]
x(-32x + 28900) = 0 \\[3ex]
x = 0 \;\;\;or\;\;\; -32x + 28900 = 0 \\[3ex]
x = 0 \;\;\;or\;\;\; -32x = -28900 \\[3ex]
x = 0 \;\;\;or\;\;\; x = \dfrac{-28900}{-32} \\[5ex]
x = 0 \;\;\;or\;\;\; x = 903.125 \\[3ex]
$
[0, 1000] by [0, 240], Xscl = 100, Yscl = 20
X = [0, 1000]
Y [0, 240]
(e.)
(f.) Part 1:
Do the process:
5: intersect again.
(f.) Part 2:
The ball has traveled approximately 88.71 feet and 814.41 feet when the height of the ball is 80
feet.
Let us convert the values in the function to display decimal values of the output
$
h(x) = \dfrac{-32x^2}{170^2} + x \\[5ex]
h(x) = -0.0011072664x^2 + x \\[3ex]
$
(g.), (h.)
To the nearest 25 feet:
The ball travels 450 feet before it reaches the maximum height of 225.778554 feet (apprxoimately
225.78 feet when rounded to two decimal places).
(i.)
To the nearest 1 foot:
The ball travels 452 feet before it reaches the maximum height of 225.77810454144 feet.